Intersoft Community - WebGrid Enterprise - access control inside template column type

access control inside template column type

handy@intersoftpt.com — Wed, 02 Jun 2010 02:47:53 GMT

Hi Ca,

You will need to use FindControl method.

e.g I am using a label named as "Label1" in a WebGridColumn.

Here is how I access the control and set the text:

 protected void WebGrid1_InitializeRow(object sender, ISNet.WebUI.WebGrid.RowEventArgs e)
 {
        Label a= (Label) e.Row.Cells[4].GetTemplateContainer().FindControl("Label1");
        a.Text = "aaa";
 }

Regards,
Handy

access control inside template column type

ismail — Wed, 02 Jun 2010 01:26:31 GMT

hi,

sorry for the mis understanding made on the question.

i know it is not possible to use HyperLinkFormatString property to asp button control.

by the above line of code i mean, i want to access the property of asp.net control used inside the template column type.

<ISWebGrid:WebGridColumn Caption="View Details" ColumnType="Template" DataMember="L_ID"
        Name="WebGridColumn11" Width="110px">
        <CellTemplate>
                      <asp:ImageButton ID="btndet" CssClass="example7" runat="server"      Text="View Details" ImageUrl="~/Images/vdetails.png" />
                      
        </CellTemplate>
     
</ISWebGrid:WebGridColumn>

Here how can i assign CssClass property from the backend exactly as i did it for HyperlinkFormatString property of hyperlink control.

access control inside template column type

andi@intersoftpt.com — Tue, 01 Jun 2010 13:47:37 GMT

Hi Ca,

As far as I know, we cannot use HyperLinkFormatString property to set the asp link button control. You can simply set the NavigateUrl in your template instead of set them in the serverside.

The HyperLinkFormatString can only be used when the column type is set to Hypelink. I hope it helps. Thank you and have a nice day.

Best Regards,

Andi Santoso

access control inside template column type

ismail — Tue, 01 Jun 2010 06:26:15 GMT

hi,

i am using "Template" columnType inside my Webgrid. If i use asp:LinkButton inside a Template, can you tell me how can access that control from the backend. Here i want to initialize the field as what i did with Hyperlink column type as shown below

WebGrid1.RootTable.Columns(1).HyperlinkFormatString = "displaymap.aspx?id=" + "{0}"

thanks and regards